List.replace_at

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replace_at(list, index, value)

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Specs

replace_at(list(), integer(), any()) :: list()

Returns a list with a replaced value at the specified index.

Negative indices indicate an offset from the end of the list. If index is out of bounds, the original list is returned.

Examples

iex> List.replace_at([1, 2, 3], 0, 0)
[0, 2, 3]

iex> List.replace_at([1, 2, 3], 10, 0)
[1, 2, 3]

iex> List.replace_at([1, 2, 3], -1, 0)
[1, 2, 0]

iex> List.replace_at([1, 2, 3], -10, 0)
[1, 2, 3]